Place the numbers 1 to 7 in the circles so that the sum of each row is 12. Mar 10, 2022 · You can solve the puzzle by moving the 2 into the same region as the 5. (If you want to keep the diagonals equal, you have to flip both columns, so only 2x2 = 4 2 x 2 = 4. ) Anyway, WLOG you can require 1 to be in the top-left Place the numbers 1 through 12 in the 12 circles so that the sum of the numbers in each of the six rows is 26. That way, one circle still has a sum of 17 and the others are made smaller by 2. Can you arrange the numbers 1 to 7 in these regions so that for each of the lines, the sums of the numbers on either side are all the same? Jan 8, 2025 · You can place the numbers 1, 3, and 6 in the first circle, 2, 4, and 7 in the second circle, and 5 in the third circle. Here are some other sums: Aug 8, 2023 · To solve the problem of placing the numbers 1 to 7 in circles so that the total of every line equals 12, we can start by understanding that we need to find a combination of these numbers that satisfies the condition. Oct 6, 2023 · The problem of placing numbers 1-7 in circles so that the sum of each line equals 12 can be solved by arranging the numbers strategically. Sep 9, 2017 · Put the numbers 1, 2, 3, 4, 5, 6, 7, 8, and 9 so the total of each row, column and diagonal add up to the same number [duplicate] Ask Question Asked 7 years, 11 months ago Modified 7 years, 11 months ago Mar 29, 2020 · It's not a spoiler to point out due to symmetry that for any valid solution, we can get 2x2 = 4 2 x 2 = 4 or 2x2x2 = 8 2 x 2 x 2 = 8 equivalent solutions by symmetry: flip L-R (swap the vertical columns), and flip each (or both) columns T-B. . Use each number from 1 to 12 exactly once. Find more possible ways? Mar 26, 2024 · The sum of the odd digits is 1+3+5+7=16, so to fill out the top-right and bottom-left circles with a combined total of 14+14=28, we need to use both the 4 and the 8 from the top-left circle. A suggested arrangement places 3 at the top, with 2, 1, and 7 to the right and 6, 5, and 4 to the left. Since the sum of each row is 12, the sum of the numbers in the outer circles must be $$12 \times 3 - C = 36 - C$$12×3−C = 36−C Apr 7, 2025 · The three lines in the figure below divide the circle into seven regions. Whether you're The sum of numbers from 1 to 7 is $$\frac {7 (7+1)} {2} = 28$$27(7+1) = 28. Dec 30, 2020 · Place the numbers from 1 to 12 in the circles without repetition to get a sum of 28, 29, 30 and 31. Place the number 1 to 12 in the 12 circles so that the sum of the numbers in the six lines of the star is 26. This video teaches you how to solve a number puzzle by using addition equations. Each straight line of three numbers will add up to 10. Jun 17, 2018 · Place the number 1 to 12 in the 12 circles so that the sum of the numbers in each of the six lines of the star is 26. Use each number from 1 through 12 exactly once. The numbers 1-7 are placed in each circle so that the total of every line is 12. pei uflwmmy nsxncbb izyda jegtng macep jccn pfis jzahtd plcfx